1. How to upload a file to Amazon S3?

    Python

    In order to upload a file to Amazon S3, you will need to create and utilize an Amazon S3 bucket and a Pulumi FileAsset object.

    The process involves the following steps:

    1. Create an aws.s3.Bucket; this is an Amazon S3 bucket that will store your uploaded file.
    2. Create a pulumi.FileAsset object; this encapsulates a file that exists on your local machine that you want to upload.
    3. Create an aws.s3.BucketObject; this represents the file that you're uploading. In the argument list to the constructor, you specify the S3 bucket to upload to (bucket), the key under which to store the file (key), and the source file (source), which points to the FileAsset object.

    Here is a Pulumi program in Python that accomplishes it:

    import pulumi import pulumi_aws as aws # Create an S3 bucket bucket = aws.s3.Bucket('my-bucket') # Specify an AWS S3 file to upload file_to_upload = pulumi.FileAsset('./file.txt') # Create the S3 bucket object bucket_object = aws.s3.BucketObject( 'my-bucket-object', bucket=bucket.id, key='example.txt', source=file_to_upload ) # Export the name of the bucket pulumi.export('bucket_name', bucket.id)

    In this program, we're first creating an S3 bucket that will host our file. We then indicate the file we want to upload using pulumi.FileAsset; in this case, the file is located in the same directory as our Pulumi program. Afterwards, we create the S3 bucket object, specifying the bucket, the key (name), and source file. The bucket's ID is then exported for easy access.

    Make sure that the file is in the same directory as your Pulumi program and that the AWS CLI is configured on the local machine.

    You can find more information on these resources in the Pulumi AWS S3 documentation.


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