1. how can I load a file from inside a component resource into an AssetArchive?

    TypeScript

    Sure! You can do this by using the pulumi.asset.FileAsset to identify the file and pulumi.asset.AssetArchive to archive it. Below is a TypeScript example where we define a new ComponentResource, and inside of it we create an AssetArchive that includes a file:

    import * as pulumi from "@pulumi/pulumi"; import { ComponentResourceOptions } from "@pulumi/pulumi/ComponentResource"; import { AssetArchive, FileAsset } from "@pulumi/pulumi/asset"; class MyComponent extends pulumi.ComponentResource { public readonly archive: pulumi.Output<AssetArchive>; constructor(name: string, opts?: ComponentResourceOptions) { super("pkg:index:MyComponent", name, {}, opts); // This assumes you have a local file named `example.txt` available. this.archive = pulumi.output(new AssetArchive({ "example.txt": new FileAsset("example.txt"), })); // To finish the initialization of this component resource, // register its outputs using `this.registerOutputs()`. // You do not ordinarily need to register inputs, but you may choose to register // outputs to ensure they are available as properties off of `this` before `this`'s constructor finishes running. this.registerOutputs({ archive: this.archive }) } } // Create an instance of the component const comp = new MyComponent("myComponent");

    Here, example.txt is the name of the local file, and we're loading it into an AssetArchive inside our MyComponent resource. This archive is then accessible from the component instance via comp.archive. This assumes that example.txt is in your Pulumi project's root directory. If it isn't, you'll need to adjust the path to the file accordingly.

    More information can be found in the Pulumi Programming Model documentation.


  2. this loads from the consuming project's path. how can I load the file from the path of the ComponentResource?

    TypeScript

    You need to compute the absolute path to the file you want to load, relative to your ComponentResource file. You can achieve that by using Node.js built-in path module. Here is an example:

    import * as pulumi from "@pulumi/pulumi"; import { AssetArchive, FileAsset } from "@pulumi/pulumi/asset"; import * as path from "path"; class MyComponent extends pulumi.ComponentResource { public readonly archive: pulumi.Output<AssetArchive>; constructor(name: string, opts?: pulumi.ComponentResourceOptions) { super("pkg:index:MyComponent", name, {}, opts); const filePath = path.join(__dirname, "example.txt"); this.archive = pulumi.output(new AssetArchive({ "example.txt": new FileAsset(filePath), })); this.registerOutputs({ archive: this.archive }); } } // Create an instance of the component const comp = new MyComponent("myComponent");

    In this example, __dirname is a Node.js variable that gets the directory name of the current module (in this case, the filepath where your ComponentResource resides). It uses the path module to join __dirname and the filename to get the absolute path. This way, it will always load the file starting from the Component's own directory path, regardless of the consuming project's path.


  3. That doesn't work in ES modules, how can I make it work there?

    TypeScript

    The issue you're facing may be related to how CommonJS modules (like the original Pulumi SDK) are imported into ESModules. In ESModules, the syntax is slightly different. You can convert the example to work with ES modules by using the import * as syntax and then referencing the constructors properly. Here is the updated code:

    import * as pulumi from "@pulumi/pulumi"; import { Output } from "@pulumi/pulumi"; import { AssetArchive, FileAsset } from "@pulumi/pulumi/asset"; import * as path from "path"; class MyComponent extends pulumi.ComponentResource { public readonly archive: Output<AssetArchive>; constructor(name: string, opts?: pulumi.ComponentResourceOptions) { super("pkg:index:MyComponent", name, {}, opts); const filePath = path.join(__dirname, "example.txt"); this.archive = new Output( new AssetArchive({ "example.txt": new FileAsset(filePath), }) ); this.registerOutputs({ archive: this.archive }); } } // Create an instance of the component const comp = new MyComponent("myComponent");

    I hope this helps! Let me know if you have further questions.


  4. no, it doesn't work because __dirname is not defined

    TypeScript

    I see you're having trouble with __dirname being undefined. This could be happening if you are using a module system other than CommonJS, such as ESM. In Node.js, __dirname is a local variable that's made available to modules by the CommonJS module system. It contains the directory path of the current module file.

    Here's how you can replicate the __dirname functionality in ESM:

    import { fileURLToPath } from 'url'; import { dirname } from 'path'; const __filename = fileURLToPath(import.meta.url); const __dirname = dirname(__filename);

    The above code creates two variables, __filename and __dirname, which are the equivalent of their CommonJS counterparts. First, import.meta.url is converted from a URL to a file path to get the file path of the current module. Then this file path is used to get the directory path.

    If you are using CommonJS (i.e., you are using require to load modules and your file extension is .js rather than .mjs), __dirname should be defined. If it's not, there's likely another issue with your code. If you're not able to resolve the issue, please provide the code that's causing this error so I can assist you better.


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