Pulumi & AWS: Modify program

Now that your S3 bucket is provisioned, let’s add a file to it. First, from within your project directory, create a new file called index.html file along with some content:

echo '<html>
    <body>
        <h1>Hello, Pulumi!</h1>
    </body>
</html>' > index.html

echo '<html>
    <body>
        <h1>Hello, Pulumi!</h1>
    </body>
</html>' > index.html

@"
<html>
  <body>
    <h1>Hello, Pulumi!</h1>
  </body>
</html>
"@ | Out-File -FilePath index.html

Now, open the program and add this file to the S3 bucket. To do this, you’ll use Pulumi’s FileAsset resource to assign the content of the file to a new BucketObject:

In index.js, create the BucketObject right after creating the bucket itself:

// Create an S3 Bucket object
const bucketObject = new aws.s3.BucketObject("index.html", {
    bucket: bucket.id,
    source: new pulumi.asset.FileAsset("./index.html")
});

In index.ts, create the BucketObject right after creating the bucket itself:

// Create an S3 Bucket object
const bucketObject = new aws.s3.BucketObject("index.html", {
    bucket: bucket.id,
    source: new pulumi.asset.FileAsset("./index.html")
});

In __main__.py, create a new bucket object by adding the following right after creating the bucket itself:

# Create an S3 Bucket object
bucketObject = s3.BucketObject(
    'index.html',
    bucket=bucket.id,
    source=pulumi.FileAsset('./index.html')
)

In main.go, create the BucketObject right after creating the bucket itself:

// Create an S3 Bucket object
_, err = s3.NewBucketObject(ctx, "index.html", &s3.BucketObjectArgs{
    Bucket:  bucket.ID(),
    Source: pulumi.NewFileAsset("./index.html"),
})
if err != nil {
    return err
}

In Program.cs, create a new BucketObject right after creating the bucket itself.

// Create an S3 Bucket object
var bucketObject = new BucketObject("index.html", new BucketObjectArgs
{
    Bucket = bucket.BucketName,
    Source = new FileAsset("./index.html")
});

In index.js index.ts main.py main.go Program.cs Program.fs Program.vb App.java Pulumi.yaml , import the FileAsset, BucketObject, and BucketObjectArgs classes, then create the BucketObject right after creating the bucket itself.

package myproject;

import com.pulumi.Pulumi;
import com.pulumi.core.Output;
import com.pulumi.aws.s3.Bucket;
import com.pulumi.aws.s3.BucketObject;
import com.pulumi.aws.s3.BucketObjectArgs;
import com.pulumi.asset.FileAsset;

public class App {
    public static void main(String[] args) {
        Pulumi.run(ctx -> {

            // Create an AWS resource (S3 Bucket)
            var bucket = new Bucket("my-bucket");

            // Create an S3 Bucket object
            new BucketObject("index.html", BucketObjectArgs.builder()
                .bucket(bucket.id())
                .source(new FileAsset("./index.html"))
                .build()
            );

            // Export the name of the bucket
            ctx.export("bucketName", bucket.bucket());
        });
    }
}

In index.js index.ts main.py main.go Program.cs Program.fs Program.vb App.java Pulumi.yaml , create the BucketObject right below the bucket itself.

name: quickstart
runtime: yaml
description: A minimal AWS Pulumi YAML program

resources:
  # Create an AWS resource (S3 Bucket)
  my-bucket:
    type: aws:s3:Bucket

  # Create an S3 Bucket object
  index.html:
    type: aws:s3:BucketObject
    properties:
      bucket: ${my-bucket}
      source:
        fn::fileAsset: ./index.html

outputs:
  # Export the name of the bucket
  bucketName: ${my-bucket.id}

This bucket object is part of the Bucket that we deployed earlier because we reference the bucket name in the properties of the bucket object.

We refer to this relationship as the BucketObject being a child resource of the S3 Bucket that is the parent resource. This is how Pulumi knows what S3 bucket the object should live in.

Next, you’ll deploy your changes.

← Previous Step Deploy changes →

Pulumi & AWS: Modify program

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